00:01
In this question we have this ts diagram as we can see here.
00:07
Now from this diagram we need to calculate different values.
00:11
So let's start with first exist temperature of the compressor.
00:16
We can write it as t2 divided by t1 which is equals to pressure p2 divided by p1 to the power gamma minus 1 divided by gamma.
00:29
Now in this case we have the values that is t2 divided by t1 which is equals to 300 which is equals to this is the ratio as a 10 to the power.
00:40
Here we have gamma that is 1 .4 minus divided by 1 .4.
00:46
On simplification we get this value of temperature t2 which is equals to 5179 .21 kelvin.
00:55
Now this is the first answer.
00:57
Now similar way we can find out.
00:59
For another part for 3 4 so we can write the ratio that is t3 divided by t 4 which is equals to p2 divided by p 1 to the power again gamma minus 1 divided by gamma on further simplification we can substitute the value that is 1200 divided by t 4 which is equals to 10 to the power 1 .4 minus 1 divided by 1 .4 divided by 1 .4 now let's simplify this to get the value of a t4 temperature that is 60021 .537 kelvin.
01:38
Now this is the solution of a first part.
01:41
Now, in the second part, let's first write down the equation of the effectiveness of the generator.
01:49
So, effectiveness we can write it as e which is equals to t2 -2 -2 -d -2 divided by t4 minus t2.
01:57
Now here this effectiveness is 1 which is equals to t2 -mines minus t2 divided by t4 dash, sorry, t4 minus t2...