00:02
Hi, in this question, using kinematic equations of motion, we can write vf square is equal to vi square plus 2 into.
00:13
In this case, the motion is upwards, so acceleration is minus g into delta y.
00:20
Now from the question, the final velocity of impala is 0 meter per second.
00:32
And we know g is 9 .8 meter per second square.
00:37
So this equation will become 0 square is equal to vi square plus 2 into minus 9 .8 into 2 .5.
00:47
From this we can get vi as 7 meter per second.
00:55
So this is the initial field of the antelope named impala.
01:08
From this we can write acceleration as delta v by delta t.
01:15
From the question we have delta t as 0 .21 seconds.
01:23
So this becomes vf minus vi that is 0 minus 7 divided by 0 .21.
01:32
So the acceleration will be minus 33 .3 meter per second square.
01:38
Now what we need to find out is the force of impala on ground.
01:53
So this will be given by f is equal to force due to impala plus weight of impala w.
02:03
So this can be given by m .a plus m .g.
02:09
So that will be m into a plus g...