An inductor in the form of a solenoid contains 420 turns, is 16.0 cm in length, and has a cross-sectional area of 3.00 cm2. What uniform rate of decrease of current through the inductor induces an emf of 175 ?V?
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The magnetic flux through a solenoid is given by the formula: Φ = B * A where B is the magnetic field strength and A is the cross-sectional area of the solenoid. Given that the cross-sectional area is 3.00 cm^2, we convert it to m^2: A = 3.00 cm^2 = 3.00 * 10^-4 Show more…
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An inductor in the form of a solenoid contains 420 turns, is 16.0 $\mathrm{cm}$ in length, and has a cross-sectional area of 3.00 $\mathrm{cm}^{2}$ . What uniform rate of decrease of current through the inductor induces an emf of 175$\mu \mathrm{V}$ ?
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