00:01
To solve for this question, formula will use voltage across the capacitor is equal to the source voltage v, 1 minus the natural log of minus the time, resistance times the capacitance.
00:16
And so this is, we'll leave up the units here.
00:20
The voltage across the capacitor is 15 volts, source voltage is 20, 1 minus e to the minus, time here is 1 .0 seconds.
00:32
Resistances are unknown and the capacitance here is 20 microferral to 20 times 10 of the minus 6.
00:39
And so now this would give me, divide by 20 from both sides.
00:44
15 over 20 is equal to 1 minus e to the minus the minus 6.
01:02
And minus 1 from both sides this would be 0 .75 there are minus 1 minus 1 of council this is 20 or take the positive of both sides 125 is equal to e to the 1 over r20 times of minus 6...