From the given current graph, we have the current \(I = 100\) mA for \(0 \leq t \leq 2\) ms.
Using the formula for voltage across a capacitor: \(V = \frac{1}{C} \int I \, dt\), where \(C = 1\) mF.
Integrating the current function from 0 to 2 ms:
\[
V =
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