00:01
Hi, so we are to solve for the percent composition of carbon in the given sample of propanol here.
00:10
Okay, so let's write solution here.
00:16
So mass percent for carbon will be equivalent to the mass of carbon over the mass of the sample, which is in this case propanol, and then multiplied by 100 percent.
00:30
So using this equation, we will solve for the mass percent of carbon in the given sample first, we will solve for the numerator mass of carbon.
00:40
If we have 2 .55 grams of propanol, c, let's write the nuclear formula here, ch3ch2ch2oh, and then we need to convert this to moles, divide the given molar mass, 60 .09 grams here, and then moles in the numerator, and then for every one mole of propanol, ch3ch2ch2oh, how many carbons do we have? we have one, two, three.
01:16
So that means we have three moles of carbon.
01:20
And then since we're solving for mass, we'll multiply the atomic mass of carbon, that's 12 grams per mole.
01:28
So now we could cancel some units, grams here, moles, moles of carbon, the remaining unit should be grams of carbon...