00:01
Here in this question an lc oscillator is given and the value of inductance l is given as 80 .0 millie henry and the value of capacitance is given as 3 .24 micro ferret so the maximum current passing through the circuit is given as 0 .84 8m .ampia and the total energy that can be written as u equal to u e plus u p ue is the energy stored in the capacitor and u b is the energy stored in the inductor at maximum current the total energy you will be u p max and it can be written as u equal to half l i max square so we can substitute the value to find the maximum energy so half into 80 .0 millie henry so 10 raised to minus 3 henry times 0 .848 milliambia times 10 rise to minus 3 a whole square so the energy stored in the lc oscillator can be calculated as 2 .876 times 10 raised to minus 8 joules.
01:46
By the conservation of energy principle, the maximum energy stored in the inductor that must be equal to the maximum energy stored in the capacitor, that is 1 by 2x2, q square by c.
02:01
So we can write q square by 2c, that is equal to, that is the maximum.
02:08
Charge q max square by 2c equal to 2 .876 times 10 raise to minus 8 joules.
02:18
From this we can find the maximum charge that can be stored in the capacitor q max equal to root of 2 into c into the total energy 2 .876 times 10 charge 2 times 3 .24 times 10 raised to minus 6 fared times 2 .876 times 10 to minus 8 jules so the maximum charge q max can be calculated as 4 .29 times 10 rise to minus 7 coulom.
03:00
For part b it is given that the current in the inductor has magnitude i equal to 0 .50 so 3 millie ampia.
03:12
So we need to find the charge on the capacitor at that instant...