An NPN BJT has Is = 2 * 10^-15 A and is operated at T = 300K. If the transistor is biased so that VBE = 0.67V, what is the collector current in mA to two decimal places?
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- \( I_S = 2 \times 10^{-15} \, \text{A} \) - \( V_{BE} = 0.67 \, \text{V} \) - \( T = 300 \, \text{K} \) Show more…
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