00:01
Hi, in this question, displacement of object attached to the spring is given as y is equal to a cos omega t.
00:29
So we can rate that the velocity would be d, y, that is equal to t by dt of a cos omega t.
00:48
That is equal to minus a omega sine omega t.
00:57
So we can write p max is equal to minus a omega as the maximum value of sine omega t is 1.
01:10
And from the question, maximum value of velocity is given as 1 .31 meter per second.
01:18
And we'll consider this as equation number 1.
01:23
Now we can write that acceleration is equal to tv by d t.
01:31
That is equal to t by d t of minus a omega sine omega t.
01:43
That will be equal to minus a omega square cos omega t.
01:52
So we can write that maximum acceleration will be equal to minus a omega square as maximum value of pose omega t is also 1...