00:01
In this problem, we are given that there is an object and this is initially moving.
00:05
So let's take its direction of movement in the right direction and its initial velocity is given as 8 .25 meter per second.
00:16
And this object is moving on a leveled surface and it's able to come to rest and that's because of the friction.
00:24
So as it comes to rest, its final velocity will be zero meter per second and this travels.
00:30
A distance of 12 meters before it comes to a complete stop.
00:35
So the displacement represented by s, that will be 12 meters.
00:40
And we are required to determine the coefficient of kinetic friction, which will be acting between the surface and the object.
00:48
So let's take mu as the coefficient of kinetic friction, which is what we have to compute, and we see that the net force which is acting on this object, it will be the friction force, which will be in the opposite direction of the motion, and that friction force is equal to mu times the normal force, where the normal force is equal to the weight of this object.
01:11
So let's take the mass as m, so the weight will be m times g, and the normal force will be m times g, and the net force is in the opposite direction.
01:20
So let's take the left direction as negative.
01:23
So we will be taking the right direction as the positive...