Given:
Distance to the object = $1.5 \times 10^{4}$ ly
Hubble parameter, $H = 21.8 \, \text{mm/s/ly}$
Time in a year = 31.5 million seconds
Extra distance = $H \times \text{Distance to the object} \times \text{Time in a year}$
Extra distance = $21.8 \,
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