An object is being acted upon by three forces and as a result moves with a constant velocity. One force is 60.0 N along the +x-axis, and the second is 75.0 N along the +y-axis. What is the magnitude of the third force?
Added by Raul A.
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Step 1: Calculate the magnitude of the third force using the formula: \[ F_{3} = \sqrt{F_{1}^2 + F_{2}^2} \] Show more…
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Three forces act on a particle that moves with unchanging velocity $\vec{v}=(2 \mathrm{m} / \mathrm{s}) \hat{\mathrm{i}}-(7 \mathrm{m} / \mathrm{s}) \hat{\mathrm{j}}$ . Two of the forces are $\vec{F}_{1}=(2 \mathrm{N}) \hat{\mathrm{i}}+$ $(3 \mathrm{N}) \hat{\mathrm{j}}+(-2 \mathrm{N}) \hat{\mathrm{k}}$ and $\vec{F}_{2}=(-5 \mathrm{N}) \hat{\mathrm{i}}+(8 \mathrm{N}) \hat{\mathrm{j}}+(-2 \mathrm{N}) \hat{\mathrm{k}}$ . What is the third force?
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