An object is thrown upward at a speed of 161 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h(t) = -16t^2 + 161t + 8 When will the height be 67 feet? (Write both results, using a comma between). Round answers to the nearest hundredth.
Added by Michele M.
Close
Step 1
Step 1:** Set the equation h(t) = 16t^2 + 161t + 8 equal to 67 feet: 16t^2 + 161t + 8 = 67 ** Show more…
Show all steps
Your feedback will help us improve your experience
Victor Salazar and 95 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An object is thrown upward at a speed of 184 feet per second by a machine from a height of 3 feet off the ground. The height h of the object after t seconds can be found using the equation h = -16t^2 + 184t + 3. When will the height be 471 feet? Select an answer: seconds When will the object reach the ground? Select an answer: seconds
Victor S.
The Wollomombi Falls in Australia have a height of 1100 feet. $A$ pebble is thrown upward from the top of the falls with an initial velocity of 20 feet per second. The height of the pebble h after $t$ seconds is given by the equation $h=-16 t^{2}+20 t+1100 .$ Use this equation for Exercises 63 and 64. (GRAPH NOT COPY) How long after the pebble is thrown will it be 550 feet from the ground? Round to the nearest tenth of a second.
Quadratic Equations and Functions
Solving Quadratic Equations by the Quadratic Formula
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD