00:01
All right, so let's say we're given the position of an object has a function of time, and it's 2 .95 t squared minus 2t plus 3.
00:15
So part a asks, what is the average velocity between 3 .3 seconds and 5 .3 seconds.
00:29
So this is just going to be the difference in the position at these two points.
00:34
So x at 5 .3 minus x at 3 .3 over two seconds.
00:43
So if we plug in the numbers, 5 .3 squared times 2 .95 minus 10 .6 plus 3.
00:53
So this will be 75 .27 minus.
00:59
The same thing for 3 .3.
01:00
So this is 28 .53 and this is over two.
01:16
And so this should be about 23 .37 meters per second.
01:23
Part b asks, what's the instantaneous speed at 3 .3 seconds? so the velocity as a function of time is going to be just going to be 5 .9.
01:37
9 t minus 2 and so the velocity at 3 .3 seconds is 3 .3 times 5 .9 minus 2 this is 17 .47 meters a second part c um or sorry we're still obtaining at velocity so at 5 .3 seconds this is 5 .3 times 5 .3 times 5 .9 minus 2, 29 .27 meters a second.
02:17
Part c, determine the average acceleration between these two times...