An object moving with uniform acceleration has a velocity of (12.0 cm/s) in the positive x direction when its x coordinate is (3.00 cm). If its x coordinate (2.00 s) later is (-5.00 cm), what is the magnitude of its acceleration in ms²
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v_i = +12.0 cm/s = +0.120 m/s x_i = 3.00 cm = 0.0300 m x_f = -5.00 cm = -0.0500 m t = 2.00 s Show more…
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An object moving with uniform acceleration has a velocity of 12.0 $\mathrm{cm} / \mathrm{s}$ in the positive $x$ direction when its $x$ coordinate is $3.00 \mathrm{cm} .$ If its $x$ coordinate 2.00 s later is $-5.00 \mathrm{cm},$ what is its acceleration?
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