An object of mass 6.89 kg has an acceleration $vec{a} = (1.29 ext{ m/s}^2)hat{x} + (-0.626 ext{ m/s}^2)hat{y}$. Three forces act on this object: $vec{F}_1$, $vec{F}_2$, and $vec{F}_3$. Given that $vec{F}_1 = (3.27 ext{ N})hat{x}$ and $vec{F}_2 = (-1.75 ext{ N})hat{x} + (1.87 ext{ N})hat{y}$, find $vec{F}_3$.