an object placed 10.0 cm from a concave spherical mirror produces a real image 8.00 cm from the mirror. if the object is moved to a new position 20 cm from the mirror what is the position of the image? is the final image real or virtual?
Added by James L.
Step 1
The mirror equation is 1/f = 1/d_o + 1/d_i, where f is the focal length, d_o is the object distance, and d_i is the image distance. Given that d_o = 10 cm and d_i = -8 cm (negative because it's a real image on the same side of the mirror as the object), we can Show more…
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