Question

An object rotating at 7.2 rev/s has a torque of 67 N*m applied to it. It stops at 3.8 s. The object's moment of inertia is?

Name: an object rotating at 72 revs has a torque of 67 nm applied to it it stops at 38 s the objects moment of inertia is 74183
Uploaded: 2023-11-09T15:04:35-08:00
Duration: 1 min 22 s
Channel: Jake Knight
Description: an object rotating at 72 revs has a torque of 67 nm applied to it it stops at 38 s the objects moment of inertia is 74183

          An object rotating at 7.2 rev/s has a torque of 67 N*m applied to it. It stops at 3.8 s. The object's moment of inertia is?

Added by Andrew R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Jake Knight

11/09/2023

Step 1

Given: Initial angular velocity, ωi = 7.2 rev/s Final angular velocity, ωf = 0 rev/s (since the object stops) Time taken, t = 3.8 s Using the formula: ωf = ωi + α*t 0 = 7.2 + α*3.8 α = -7.2/3.8 α = -1.89 rev/s^2 Show more…

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