Question

An object with a mass 3.3 kg is executing simple harmonic motion, attached to a spring with spring constant 310 N/m. When the object is 0.025 m from its equilibrium position, it is moving with a speed of 0.50 m/s . 1. Calculate the amplitude of the motion. 2. Calculate the maximum speed attained by the object. please answer both questions, thank you

          An object with a mass 3.3 kg is executing simple harmonic motion, attached to a spring with spring constant 310 N/m. When the object is 0.025 m from its equilibrium position, it is moving with a speed of 0.50 m/s .
1. Calculate the amplitude of the motion.
2. Calculate the maximum speed attained by the object.
please answer both questions, 
thank you
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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An object with a mass 3.3 kg is executing simple harmonic motion, attached to a spring with spring constant 310 N/m. When the object is 0.025 m from its equilibrium position, it is moving with a speed of 0.50 m/s . 1. Calculate the amplitude of the motion. 2. Calculate the maximum speed attained by the object. please answer both questions, thank you
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Transcript

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00:01 The mass of the object is given as m equal to 2 .7 kg and the mass execute a simple harmonic motion and it is attached to a spring with a spring constant k equal to 3 tonne no ton per meter it is given that when the object is 0 .02 meter from its equilibrium position so the displacement x equal to 0 .022 meter and it is moving with the speed v.
00:53 0 .55 meter per second and we need to find the amplitude of the motion and the maximum speed attained by the object.
01:05 So according to the principle of energy conservation, total energy e can be written as the potential energy stored in the spring plus for the sum of the potential energy and the kinetic energy.
01:32 So we can substitute the values, that is, half, k is 3 ton, no ton per meter, and x is 0 .02 meter per square.
01:49 Plus half into mass is 2 .7 kg times the speed of the object that is 0 .55 meter per second per square.
02:08 So the total energy of the object executing the simple harmonic motion can be written as 0 .07575...
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