An object with a net charge of +10 mC moves with speed 20m/s through a magnetic field with magnitude 5 T. If the force exerted on the charge by the field is 0.5 N, what is the angle between the object’s velocity and the field
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Step 1
- The net charge of the object is +10 mC (milliCoulombs), which is equivalent to +10 × 10^-3 C (Coulombs) because 1 mC = 10^-3 C. - The object moves with a speed of 20 m/s. - The magnetic field's magnitude is 5 T (Tesla). - The force exerted on the charge by the Show more…
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