An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s). If a particular disk is spun at 998.0 rad/s while it is being read, and then is allowed to come to rest over 0.435 seconds, what is the magnitude of the average angular acceleration of the disk? average angular acceleration: rad/s^2 If the disk is 0.12 m in diameter, what is the magnitude of the tangential acceleration of a point 1/8 of the way out from the center of the disk? tangential acceleration: m/s^2
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We can use the formula: ωf = ωi + αt where ωi = 998.0 rad/s, ωf = 0 rad/s, t = 0.435 s, and α is the angular acceleration we want to find. Rearranging the formula, we get: α = (ωf - ωi) / t α = (0 - 998.0) / 0.435 α = -2290.8 rad/s^2 Note that the negative Show more…
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