00:01
In this problem, we're given an organic compound with the empirical formula c4h7bro2.
00:10
We're given an nmr spectrum that we want to now analyze so we can figure out what our structure would be.
00:17
Now the first thing you always want to do is find degrees one saturation.
00:21
This will tell you how many pi bonds and rings you have collectively in your structure.
00:25
So we take two times the number of carbons, add two, subtract the number of hydrogens, and then also subtract the number of bromines, and then divide by two.
00:41
So we have ten minus eight over two, so we get one.
00:45
So we have a ring or a pi bond.
00:49
From there we start to look at our structure.
00:51
Now notice how at eleven we have a singular peak.
00:59
That's going to be pretty typical for an aldehyde...