00:01
We are asked to consider an organic compound, we will reference a z, that contains carbon, hydrogen, and oxygen only.
00:07
We are given 40 % and 53 % carbon and oxygen.
00:14
So my percent hydrogen will be equal to 100 minus 40 minus 53 .33 equals 100 minus 40 minus 53 .33.
00:31
That will be 6 .67.
00:34
Let's make that look a little bit better.
00:43
Okay, so i know all my percents.
00:45
My first order of business is going to be to find my empirical formula.
00:54
Super easy.
00:55
That's percent to mass, and i've got 40 % c.
01:00
I like to do my h next.
01:03
6 .67 % h and 53 .33 % c.
01:12
It's a little poem we use that's called percent to mass.
01:15
Super easy, just change that to g.
01:17
Percent to mass, mass to mole.
01:21
Next we're going to convert each of these to mole by dividing by the molar mass.
01:28
For these three particular elements, i just use my molar masses to one decimal.
01:42
And this will equal 40 divided by 12.
01:45
Whoopsie, i wrote 410.
01:46
40 divided by 12...