00:01
We are given that there is an owl which is at a height 15 meter above the ground and it is flying with some horizontal speed which is given to us 16 meter per second.
00:21
This value is given to us.
00:24
Now what happens is a mouse which this owl was carrying with him, it starts to fall from here.
00:31
So it will definitely hit ground.
00:36
After some time, it will hit the ground.
00:38
So now what will happen in the journey is the horizontal speed as we know will not change.
00:44
The horizontal speed of the mouse will remain 16 meter per second.
00:50
But the vertical speed will start to increase.
00:54
Okay.
00:54
And definitely when it falls the falls here on the ground, there would be some vertical component of the speed.
01:03
And this horizontal component of the speed we already know is 16 meter per second.
01:10
Now the total speed, as a matter of fact, as we know, would be equal to vx square plus vy square and then whole route.
01:24
This would be this would be the speed basically...