00:01
All right, we're going to find the structure of an unknown compound of compound d.
00:08
First, let's take a look at the data given to us from our ir spectrum.
00:14
Looking at a table like this or something similar from your own class, we can see that this is indicating the presence of a carbonyl group, carbon double bond at nutrient oxygen.
00:24
Now we're ready to look at our proton nmr data.
00:27
So looking at a chart like this or something similar from your own class, we can see that this singlet right here, this is going to indicate the presence of an aldehyde group.
00:43
So c -h -o.
00:46
Now we have two doublets here, and these are in a range not only for an aromatic ring, but because we have two doublets, we know that it will be a dye, sublottes.
01:00
Prostituted para -aromatic rain.
01:03
That will look like a little small.
01:14
There we go.
01:17
All right.
01:18
And then here we're going to have our next doublet that indicates the presence of a methylene group.
01:28
So, ch2.
01:32
And lastly, oops, a little stray mark there.
01:36
There we go.
01:38
And lastly, our triplet is showing us.
01:44
The presence of a methyl group, so a ch3 group.
01:48
All right, and then these two together are methylene and our methyl group.
01:55
For here, those are going to form an ethyl group.
02:01
All right, now we're probably ready to put together a form of our structure and see how close we are.
02:07
So, let's start with our para dissubstuted aromatic ring.
02:17
We know that it's, that would be a paracinfiguration, and we need to add our double bonds.
02:25
There we go.
02:26
All right.
02:27
On one side, we're going to add our, our ethyl group...