00:02
So for this problem, we're given the following valence electron configuration for an element that is unknown.
00:11
So in this problem, we need to determine how many valence electrons there are.
00:17
So we simply add the two superscripts to find out that there are six valence electrons in this unknown element.
00:33
So because we know there are six valence electrons, the possible elements that could take this.
00:38
Configuration are any elements from group 6a on the periodic table.
00:43
So oxygen, sulfur, selenium, tularium, polonium, or lv are all possible elements for this balance electron configuration.
01:13
So now we need to determine what formula this element will create with a lithium ion.
01:21
We know a lithium ion always takes a plus one charge and a group six element always takes minus two.
01:34
So if we crisscross those, we'll get a final answer of li, 2, and then an x for our unknown element...