00:01
In this problem, we're giving a fluid of mass equals 3 kilograms, and the volume is given to us as 1 liter.
00:13
Now we're asked to find the density row, the specific volume, we're also asked to find the specific weight, which i'll call gamma, and this is a...
00:28
There we go, that's a fancy v for specific volume.
00:31
And d we're trying to find the specific gravity and so let's go ahead and calculate density first so before calculating density we want to convert our liters to our si unit of meters cubed so the unit conversion for one liter to meters cubed is going to be 10 to the well we can just go and write this out as 10 to the negative third meters cubed.
01:10
And one density that we also will need later in these calculations, at least for the specific gravity, will be the density of water, which is equal to 10 to the third kilograms per meter cubed, and gravity, which is equal to 9 .81 meters per second squared.
01:39
So in calculating the density, we're going to get density is equal to mass over volume.
01:50
And so our mass is three kilograms.
01:53
We converted our density to the proper si unit.
01:59
So now when we solve for the volume, or excuse me, when we solve for the density, we get three divided by 10 to the negative third.
02:09
And we'll be solved, we get a density of 3 ,000 kilograms per meter cubed.
02:21
And so this is our density.
02:24
And i'll just read it over here as 3 times 10 to 3 kilograms per meter cubed.
02:41
And so next we're going to compute the specific volume.
02:45
And the specific volume is equal to the volume divided by the mass.
02:52
And so in doing this, we get a value of, that should actually be inverse of that.
03:05
So we're going to get 3 .333 times 10 to the negative 4th.
03:20
And our unit for that is going to be equal to meters cubed per kilogram...