00:01
Empirical formula is the simplest formula of a compound.
00:06
In this problem, we're given with a compound which contains carbon, hydrogen, and oxygen.
00:13
So we generalize its formula as cx, h, cx, h oz.
00:17
The mass of this compound is, so let's say mass of compound is equal to 1 .6, rather, 1 .6 grams.
00:28
This mass of the compound is combusted so that it forms carbon dioxide and water which masses are given to be equal to 3 .76 .1 grams and 1 .0286 grams respectively.
00:51
We wish to find the empirical formula of this compound.
00:56
So find formula.
00:58
So we assume that all of the carbon in the compound turns into co2 and all of the hydrogen turns into water so that we can solve for the most of carbon from the given amount of carbon dioxide.
01:14
So let's first convert the given mass of carbon dioxide into most by dividing it with the molar mass of co2, which is 44 .01 grams.
01:26
And then from the formula of co2 we find that for every one mole of the compound we have one more of the carbon so we're gonna divide 3 .7681 by 40 .0 .01 giving us the most of carbon which is 0 .08562.
01:49
Let's also convert this into grams of carbon.
01:52
We just need to multiply the most by the motor mass of carbon.
01:58
The motor mass being the atomic mass of the element just expressed in the unit of grams per moon.
02:06
So therefore we have 1 .028.
02:14
Next let's find the most of hydrogen...