Question

An unstable nucleus within an ion-beam travels with velocity v = ? c where c = 3.00 × 108 m.s?1 and ? < 1. As the ions travel they randomly undergo nuclear decay, emitting an ?-particle. On average they are observed to decay after traveling a distance of 6.20 m. The same ions are brought to rest and held stationary in an ion-trap. The observed decay time of ions in the ion-trap is 10 ns. What is the value of ?, where the velocity of the ion beam is v = ? c?

          An unstable nucleus within an ion-beam travels with velocity v = ? c where c =
3.00 × 108 m.s?1 and ? < 1. 

As the ions travel they randomly undergo nuclear decay, emitting an ?-particle. On average they are observed to decay after traveling a distance of 6.20 m.

The same ions are brought to rest and held stationary in an ion-trap. The observed decay time of ions in the ion-trap is 10 ns.

What is the value of ?, where the velocity of the ion beam is v = ? c?

Added by Esther R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Chapter 37

Instant Answer

Solved by Expert Dharmendra Maheshwari

Step 1

First, we need to find the time it takes for the ions to travel 6.20 m in the ion-beam. We can use the formula: distance = velocity × time. Show more…

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An unstable nucleus within an ion-beam travels with velocity v = ? c where c = 3.00 × 108 m.s?1 and ? < 1. As the ions travel they randomly undergo nuclear decay, emitting an ?-particle. On average they are observed to decay after traveling a distance of 6.20 m. The same ions are brought to rest and held stationary in an ion-trap. The observed decay time of ions in the ion-trap is 10 ns. What is the value of ?, where the velocity of the ion beam is v = ? c?