stion 5 of 8 Macmillan Learning An urn contains 2 red and 2 green marbles. We pick a marble, record its color, and replace it. We repeat this procedure a second and a third time. Identify the probability distribution for the number of red marbles. Number of red marbles Probability 0 1 2 3 1/8 1/4 1/4 1/8 Number of red marbles 0 1 2 3 Probability 1/4 3/8 3/8 1/4 Number of red marbles 0 1 2 3 Probability 1/4 1/2 1/2 1/4 Number of red marbles 0 1 2 3 Probability 1/8 3/8 3/8 1/8
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Since there are 2 red marbles and 2 green marbles, the probability of drawing a red marble is: \[ P(\text{Red}) = \frac{2}{4} = \frac{1}{2} \] Show more…
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An urn contains two red and two green marbles. We pick one marble, record its color, and replace it before picking the second marble. We repeat this procedure a third time. The probability distribution for the number of red marbles is given by Number of red marbles 0 1 2 3 Probability 1/8 3/8 3/8 1/8 For this distribution, the probability two or more red marbles is given by: 1/4. 6/8. 1/2. 3/8.
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An urn contains 10 marbles: 4 RED, 3 BLUE, 2 WHITE, and 1 GREEN. We will make 5 draws from this urn, one at a time, without replacement. Find the probability that the 5th draw is white: 2/10 Find the probability that the first draw is red AND the second draw is white AND the third draw is blue: 24/720 Find the probability that the first draw is green OR the second draw is green OR the third draw is green OR the fourth draw is green OR the fifth draw is green: 1/100,000 Find the probability that the first draw is red OR the second draw is red: 12/90 Find the probability that the first draw is blue OR the second draw is blue OR the third draw is blue: 1-(210/720)
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