00:01
Hello students let us do this question.
00:05
One contains two red and four blue balls.
00:12
So total there are six balls.
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Part a, three balls are selected at once, all at once.
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Probability of getting two blue and one red ball.
00:29
So this is number of ways of getting two blue balls from four blue ball and one red ball from two red ball.
00:36
So this will be 4c2 into 2c1 divided by total number of ways of selecting be from 6 balls.
00:46
So 6c3.
00:48
This will be 6 into 2 divided by 20.
00:53
Simplifying it we get it as 3 by 5.
00:57
So probability of getting 2 blue and 1 red ball when all 3 are selected all at once is 3 by 5.
01:05
Part b 3 are selected 3 are selected.
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With replacement.
01:09
We are asked to find probability of first and third ball are blue.
01:20
So this will be first is blue, then second will be red, then third will be blue.
01:28
So this is for first selection blue, there are four blue balls.
01:34
So probability of getting first blue ball is four by six.
01:38
Then getting second as red is there are two red balls...