An urn contains 3 green balls, 2 blue balls, and 4 red balls. In a random sample of 5 balls, find the probability that both blue balls and at least 1 red ball are selected.
Added by Richard G.
Step 1
This can be calculated using the combination formula C(n, r) = n! / [r!(n-r)!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial. So, the total number of ways to draw 5 balls from 9 is C(9, 5) = 9! / [5!(9-5)!] Show more…
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