00:01
Hello student, here in the given problem, first we are interested in finding the number of red balls drawn before the first black ball is chosen.
00:11
Let us define the indivisible event xi.
00:15
Each xi equal 1 if red ball i is drawn before any black ball and 0 otherwise.
00:47
So, first answer is x is equal to x1 plus x2 plus x3 plus up to xr.
01:01
Now, the second answer to find the expected value of x.
01:06
Here we can sum up the expected value of each xi.
01:10
Here for each xi, the probability that red ball is drawn before any black ball is the which is divided by the number of ways to arrange the all the r plus b balls.
01:22
Therefore, here for each xi, the probability that red ball i is drawn before any black ball is divided by number of ways to arrange all r plus b balls.
02:28
Therefore, expected value of x is equal to probability of x1 is equal to 1 plus probability of x2 is equal to 1 plus probability of x3 is equal to 1 plus up to probability of xr is equal to 1.
02:49
Here we know that this combination is nothing but c of r minus 1 and r minus 1 plus b which is divided by c of r plus b and r plus b...