Analysis of a carbohydrate showed that it consisted of 40.0% C, 6.71% H, and 53.3% O by mass. The molecule's molar mass was found to be about 150 g/mol. What is the molecular formula of this compound?
Added by Jennifer G.
Step 1
- Assume we have 100g of the compound. - 40.0% C = 40.0g C - 6.71% H = 6.71g H - 53.3% O = 53.3g O Show more…
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