Question

Analyze the following code. class Test { public static void main(String[] args) { String s="123"; System.out.println("s is " + s); } } The program has a runtime error because s is null in the printin statement. The program has a runtime error because s is not initialized, but it is referenced in the printin statement. The program has a compilation error because s is not initialized, but it is referenced in the printin statement. The program compiles and runs fine.

          Analyze the following code.
class Test {
public static void main(String[] args) {
String s="123";
System.out.println("s is " + s);
}
}
The program has a runtime error because s is null in the printin statement.
The program has a runtime error because s is not initialized, but it is referenced in the printin statement.
The program has a compilation error because s is not initialized, but it is referenced in the printin statement.
The program compiles and runs fine.

Analyze the following code.
class Test
public static void main(String[] args)
String s="123";
System.out.println("s is " + s);

The program has a runtime error because s is null in the printin statement.
The program has a runtime error because s is not initialized, but it is referenced in the printin statement.
The program has a compilation error because s is not initialized, but it is referenced in the printin statement.
The program compiles and runs fine.

Added by Rodrigo B.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Chapter 7

Instant Answer

Solved by Expert Vaibhav Jain

Step 1

Then, it prints the string "s is " concatenated with the value of `s`. Since `s` is initialized with the value "123", it is not null and there is no runtime error. Show more…

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Analyze the following code: public class Test { public static void main(String[] args) { String s = "123"; System.out.println("s is " + s); } } The program has a runtime error because s is null in the println statement. The program has a runtime error because s is not initialized, but it is referenced in the println statement. The program compiles and runs fine. The program has a compilation error because s is not initialized, but it is referenced in the println statement.