Question

Complete the calculate_cars_needed(number_of_people, number_of_seats) function that takes the number of people to be transported and the capacity of each car as parameters. The function then prints the number of cars needed. For example: Test Result calculate_cars_needed(10, 4) 3 cars needed for 10 people. calculate_cars_needed(4, 5) 1 car needed for 4 people.

          Complete the calculate_cars_needed(number_of_people, number_of_seats) function that takes the number of people to be transported and the capacity of each car as parameters. The function then prints the number of cars needed.
For example:
Test
Result
calculate_cars_needed(10, 4)
3 cars needed for 10 people.
calculate_cars_needed(4, 5)
1 car needed for 4 people.
        
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Complete the calculatecarsneeded(numberofpeople, numberofseats) function that takes the number of people to be transported and the capacity of each car as parameters. The function then prints the number of cars needed.
For example:
Test
Result
calculatecarsneeded(10, 4)
3 cars needed for 10 people.
calculatecarsneeded(4, 5)
1 car needed for 4 people.

Added by Vanesa E.

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Computer Science and Information Technology
Computer Science and Information Technology
Trishna Knowledge Systems 2018 Edition
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And the capacity of each car as parameters. The function then prints the number of cars needed. For example: Test Result calculate_cars_needed(10, cars needed for 10 people calculate_cars_needed(4, 15 1 car needed for 4 people
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Transcript

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00:01 The first things first we define our variables.
00:03 I'm going to say v equals the number of vans we have, or no, seats.
00:08 V is the seats in vans, and i'm going to say v is the seats in buses.
00:19 So we know that we have three vans and six buses with 159 students.
00:28 Three vans, six buses, 159 students, and all the seats are filled.
00:37 So the other high school has five vans and five buses with 155 students.
00:51 So if we want to solve this, we have to do one or two things.
01:00 We can either use substitution or elimination.
01:04 And in this situation, i'm going to go ahead and use elimination.
01:10 So what i'm going to do is i'm going to multiply this top equation by 5, and i'm going to multiply this bottom equation by 3, and then i'm going to subtract them.
01:25 So when we do this, 5 times 3 is 15, 3 times 5 is 15, 15 minus 15 is 0.
01:35 5 times 6 is 30, 3 times 5 is 15, 30 minus 15 is positive 15b, and then 15 times 5 is 795, 15 times, or 155 times 3 is 465, so 795 minus 465 is 330...
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