Anna has a Subaru Impreza with a car battery that isn't feeling well. The battery has an emf of 11 V and an internal resistance of 0.01 Ω. Internal resistance is like having a battery connected to a resistor in series. To help the ailing battery, she hooks a second battery with an emf of 12 V and an internal resistance of 0.01 Ω, using a jumper cable with a total resistance of R = 0.03 Ω to the terminal of the first battery.
(a) Draw a diagram of the circuit.
(b) Use Kirchhoff's loop rule to find what the charging current should be.
(c) Find the total power dissipated in the circuit.
(d) What if Anna connected the battery terminals in reverse? What would the current be? Should this answer be larger or smaller than your answer to part (b)?