00:01
Hello students, let's to this question.
00:02
Here the conference level that is 1 minus alpha equal to 95 % equal to 0 .95 is given.
00:08
Now we know that the value of z at 95 % equal to 1 .96.
00:14
So first we have to calculate the standard deviation.
00:17
So here standard division becomes sigma equal to range divided by 4 and range is nothing but largest minus smallest observation.
00:26
Then margin of error ame equal to x alpha by 2 into sigma upon square rate of n so first we find out the range therefore we gave the value of sigma equal to range that is 58 ,000 8 -800 minus 41 ,000 divided by 4 equal to 17 ,800 divided by 4 4 ,000 4 ,000 per 50 then it is given that margin of lme equal to 5 1 1 1 1 1⁄2 which implies that 5 1 .96 into 4 ,000 .6 into 4 ,000.
01:00
4 ,4005 divided by square rate of n implies that square root of n equal to 17 .444.
01:09
Therefore n equal to square of this equal to 304 .293, which means that n is approximately equal to 3004.
01:18
Now next, margin of error m .e equals 2 .00 implies that 200 equal to 1 .96 into 4 ,4005 divided by square rate of n...