ANOVA grade Sum of Squares df Mean Square F Sig. Between Groups 44.067 2 22.033 2.961 .069 Within Groups 200.900 27 7.441 Total 244.967 29 Interpret the table above. a. Reject the Null Hypothesis. b. Fail to Reject the Null Hypothesis. c. p < .05 d. p > .05 e. a and c f. b and d
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First, we see that this is a table for an ANOVA analysis, which is used to compare the means of three or more groups. Show more…
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Stats. Complete the following ANOVA summary table. ___________________________________________________________ Source Sum of Squares df Mean Square F _____________________________________________________ Between groups 75.0 4 Within groups 101.5 26 Total 176.5 30 MSB = (3 decimals) MSW = (3 decimals) Fobt = (3 decimals) Fcv (critical value) at p< 0.05= Conclusion: A) Reject Null Hypothesis or B) Fail to Reject Null Hypothesis Answer A or B, letter only:
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