00:01
Hello, so let's first talk about the this is the parallel connection so the equivalent capacitance so the total capacitance will just be c1 plus c2 for parallel, right? we're not just going to be 5 micro -faird plus 12 micro -fariads so that's just thing my profile as total capacitance then the potential difference across each capacity so for a parallel connection they have the same potential difference across them right so if you put a volt meter right here it's going to measure nine volts if you put a volt meter right here it's going to measure nine volts so so the pd across each is 9 volt for the parallel connection.
01:18
Now let's look at the charge in each capacity.
01:26
So the charge, for example, charge 1 is equal to c1 and v, right? so the charge on c1, which is going to be in the value of c1 times potential difference in 9 volts, right? so this is just going to be 45 microculems.
01:56
Let's look at the charge on capacity 2.
02:00
That's just c2 and v.
02:03
It's just going to be, let's check the value of c2.
02:07
That's 12.
02:10
So that's 12 micro -farrad times 9.
02:17
12 times 9 is 108.
02:20
That's 108.
02:25
Microculum so that is for the parallel connection let's talk about the series so for the series connection the total capacitance is given by one over c1 plus one over c2 inverse so it's going to be a one over five microculum plus one over 12 microculum inverse so let's put this in a calculator and see what we get so we have one divided by five one divided by five i'll be cross one divided by twelve what that gives us that gives 17 over 60 so ct gives you 17 over 60 micro -farrant.
04:18
So remember, this is inverse, right? so what we're going to get, total capacitance is going to be 60 micro -farrad over 17.
04:34
So this is what we get as the total capacitance.
04:39
The second part of the question will be to find the what? the potential difference? okay.
04:46
So to get the potential difference, so this is a serious connection.
04:50
So they have different potential differences, right? so what we can do is to first find the charge that is going through the system.
04:59
So let's find the charge...