00:03
Here in this problem, given 0 .246 molar lead nitrate and reacting with 36 milliliter of 0 .3 to 2 molar kcl, the reaction is given.
00:15
We have to find out how many milliliters of lead nitrate is reacting.
00:20
Now here from the equation we can see one more lead nitrate requires 2 moles of potassium chloride to react.
00:27
Now 36 milliliter of 36 milliliter of 0 .322 molar kcl means how many moles we'll figure out that.
00:42
36 milliliter means 36 divided by 1 ,000 liter times concentration 0 .322 moles per liter.
00:56
That is we will have 0 .0116 mole kcl potassium chloride.
01:09
Now from the equation we see 1 mole kcl requires 2 moles of lead nitrate pb, no3 hold twice.
01:30
Therefore moles of lead nitrate no two moles kl two moles kcal requires one more lead nitrate one mold of lead nitrate therefore mole of lead nitrate required here 0 .0116 divided by 2, that is 0 .0058 mole of lead nitrate required.
02:24
Now, number of mole of lead nitrate, that is volume in liter, say x liter, times molarity, molar concentration that is 0 .246 molar...