Question

An AC voltage of the form \(\Delta v = 100 \sin 1000t\), where \(\Delta v\) is in volts and \(t\) is in seconds, is applied to a series RLC circuit. Assume the resistance is 395 \(\Omega\), the capacitance is 5.15 \(\mu F\), and the inductance is 0.500 H. Find the average power delivered to the circuit.

          An AC voltage of the form \(\Delta v = 100 \sin 1000t\), where \(\Delta v\) is in volts and \(t\) is in seconds, is applied to a series RLC circuit. Assume the resistance is 395 \(\Omega\), the capacitance is 5.15 \(\mu F\), and the inductance is 0.500 H. Find the average power delivered to the circuit.
        
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An AC voltage of the form Δ v = 100 sin 1000t, where Δ v is in volts and t is in seconds, is applied to a series RLC circuit. Assume the resistance is 395 Ω, the capacitance is 5.15 μ F, and the inductance is 0.500 H. Find the average power delivered to the circuit.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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answer correctly #4 4.[-/1Points] DETAILS SERPSE1032.6.OP.015. MY NOTES ASK YOUR TEACHER An ACvoltage of the form Av= 100 sin 1 000t,where v is in volts and tis in seconds,is applied to a series RLCcircuitAssume the resistance is 395,the capacitance is 5.15 Fand the inductance is 0.500 H.Find the average power delivered to the circuit. M
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Transcript

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00:01 In this question, it is given to us an ac voltage of the form delta v equals to 100, sine 1000 t.
00:13 Where delta v is in bolts and t is in second is applied to a series rlc circuit.
00:21 Assume the resistance is equal to 450 -oom capacitance is 5 .35 micro -fodd.
00:38 And an induction i is equal to 0 .500 henry.
00:46 We need to find out the average power delivered to a circuit.
00:49 Average power delivered to circuit.
01:03 So the solution for this question is let's take delta v is equals to 100 sign 1000p.
01:15 We call it as our first occasion and delta v is equal to vmax, sine, omega, t, this is our second location.
01:35 So from first and second location we get, from first and second location we get, vmax is equal to 100 volts.
01:52 And since we know that vrms is equals to vmax divided by under root 2, which is equals to 100 divided by under root 2 which is equal to 7 .7 volts.
02:10 Thus our omega is equals to 1000 which is equals to 2 pi f...
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