Question

Chapter 6, Problem 6/002 ? Incorrect The 462-N force is applied to the 86-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force \(F\) exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left. \(\mu_s = 0.71\) \(\mu_k = 0.55\) Answer: \(F = -450\) N \(P = 462\) N

          Chapter 6, Problem 6/002
? Incorrect
The 462-N force is applied to the 86-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force \(F\) exerted by the horizontal
surface on the block. The force is positive if to the right, negative if to the left.
\(\mu_s = 0.71\)
\(\mu_k = 0.55\)
Answer: \(F = -450\) N
\(P = 462\) N

Chapter 6, Problem 6/002
? Incorrect
The 462-N force is applied to the 86-kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal
surface on the block. The force is positive if to the right, negative if to the left.
= 0.71
= 0.55
Answer: F = -450 N
P = 462 N

Added by Nathan F.

Fundamentals of Physics

David Halliday, Robert Resnick, Jearl… 10th Edition

Chapter 6

Instant Answer

Solved by Expert Jacob Fry

Step 1

The gravitational force is given by the formula Fg = m * g, where m is the mass of the block and g is the acceleration due to gravity. In this case, m = 86 kg and g = 9.8 m/s^2. Therefore, Fg = 86 kg * 9.8 m/s^2 = 843.6 N. Show more…

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Answer is NOT 450 or -450. I had found N=633.916 but I am not sure where I went wrong. PLEASE HELP! WILL RATE! Chapter 6, Problem 6/002 Incorrect The 462 N force is applied to the 86 kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left. P = 462 N âˆš27 = 0.71 = 0.55 Answer: F 450