00:01
So in this problem, we're given this equation x to the third minus 14x minus 8.
00:04
In part a, the first thing we want to do is we want to use the rational zeros theorem to find the list of all of our rational zeros.
00:12
Well, to do this, what we need to do is we're going to take the factors of our constant term, which is negative 8, and we divide that by the factors of our leading coefficient, which is 1.
00:21
Well, the nice thing, because it's the factors of 1, that part actually won't cancel.
00:26
So really, we just need our factors in negative 8, which we plus or minus 1, plus and minus 2, plus and minus 4, and plus and minus 8.
00:34
So if you're looking at your list, in this particular case, the answer would be choice d.
00:38
So that's the answer to part a.
00:40
Now, in part b, what they've said is to use synthetic division to test some of these rational zeros to figure out which one is, in fact, in actual room.
00:49
So essentially, you could pick any number that you want.
00:51
So in this case, i'm going to use four.
00:53
So if i take four, that's going to go in our little half box, then i'm going to down our coefficient for each term.
00:59
Now keep in mind you're missing your x -square term, so you have to put the 0 in its place.
01:03
So you'll have 1 -0 -negative -14 as negative 8.
01:07
Then i'm going to leave a line in the space and bring down our 1.
01:10
Then we're going to multiply 1 by 4, which is 4, and then we add 0 plus 4 is 4.
01:15
And we'll continue this process.
01:17
4 times 4 is 16, negative 14 plus 16 is equal to 2, 2 times 4 is 8, and negative 8 plus 8 is 0.
01:24
Perfect.
01:25
So now what we've found is that 4 is one of our roots.
01:29
So that's the answer to the part b.
01:31
Now lastly, part c, they want us to use this result to find the remaining roots...