Answer the following questions based on the PERT chart below with task times given in hours. [All answer should be given as a single number only without units]. A(5) E(5) Start B(1) D(8) F(1) H(4) End C(6) G(3) I(7) a. The number of priority lists that can be created for this project is b. The average time for 3 processors for this project is c. The critical time for this project is hours. hours. d. The lowest finishing time for which you could claim a schedule for two processors is optimal is hours. hours. e. The lowest finishing time for which you could claim a schedule for four processors is optimal is f. The earliest time that task E could be started by a processor in any schedule with any number of processors for this project would be hours after the start of the project.
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There are 5 tasks (A, E, H, G, and the 6-hour task). We can arrange them in any order, so there are 5! (5 factorial) priority lists. 5! = 5 × 4 × 3 × 2 × 1 = 120 Show more…
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