00:01
First of all, let's have a look what all is given in the problem.
00:04
Given is a structure of a molecule is given.
00:08
The structure that is given is the terminal one is cf3, which is attached to co.
00:15
This side we have is nh and this is attached to next carbon atom that is attached to tertiary butyl group.
00:22
This is attached to again co.
00:25
Here is the nitrogen atom which is attached to a cyclic ring like this.
00:30
And this is attached to a cyclopropane ring, which is attached to carbonyl carbon -carbon -n -h -n -h again co -n -h bond is present.
00:40
Here is the substituent that is cynogro and this is again a cyclopentane ring with n -h.
00:47
So, here what we have to find out is we need to find out the number of pi bonds in it.
00:52
We need to find out the number of pi bonds.
00:55
How many non -bonding electron pairs are there? non -bonding electron pairs.
01:00
What is the molecular formula of the compound and we need to specify the hybridization at nitrogen atom hybridization and nitrogen atom so let's try to look at this first let's try to calculate the pi bonds so this is one of the pie bond second pi bond third pi bond so the number of pi bonds test is there is three after that we have to tell about the non -bonding electrons let's count the non -bonding electrons here we can see that each flow is going to have three loan pairs.
01:32
So total of 3 -33.
01:36
That means we can say that six loan pairs, 18 electrons.
01:40
This is going to have two lone pairs, 19, 20, 22, 23, 24, 25, 26, 27, 27, 28, 29, 30, 30, 31, 34.
01:52
After that, this nitrogen is also going to have 35, 36, 37, 38, 39, 40.
01:59
Total of we can say that 40 non -bonding electrons will be there.
02:04
After that we have to tell the molecular formula of the compound.
02:08
So let's count the carbon atoms.
02:10
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 14, 15, 16, 17, 18, 19, 20, 21, 22, 22, 23.
02:24
So, total of carbon atoms is c -23...