Answer the following short questions: a) Is 2n+1 = 0(2^n)? b) Is 2^2n = 0(2^r)? c) f(n) = O(log(n)) implies g(n) = O(f(n)) d) f(n) = O(f(n))
Added by Gregorio R.
Step 1
By definition, 2n+1 = O(2^n) if there exist constants c > 0 and n₀ > 0 such that 2n+1 ≤ c·2^n for all n ≥ n₀. Show more…
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