00:01
Hi, in this question we need to give the iupac name of the following compound.
00:04
So it is 1 2 1 1 2 3 4 5.
00:11
So it will be 3 -bromopentyl -ethyl -methyl -amine.
00:27
So this is 3 -bromopentyl -ethyl -methyl -amine.
00:35
The second part of the question is we need to write the condensed structure of o -n -h -l -ethyl group.
01:00
So this can be written as cl -c6h4 -c0 -nh -ch2 -ch3.
01:10
Then the third part of the question that is we need to write the iupac name for the compound o -e -t methyl group is there.
01:24
So this is 1 2 3 4 5.
01:30
So it is penta right.
01:33
So ethyl 2 -methyl -3 -oxopentanoate.
01:45
So this is the iupac name.
01:47
So ethyl 2 -methyl -3 -oxopentanoate right.
01:54
Then the d part.
01:57
So here they have given ch3 -ch2 -c double bond o -n -ch3 twice.
02:08
This is n ,n -dimethyl -amide which is converted to enolate ion form.
02:25
What is the reagent used for this? that is lda.
02:29
The lda is lithium isopropyl amine.
02:39
This is the structure of lda.
02:40
This lda is used to convert n ,n -dimethyl amide to enolate form.
02:46
Then next part of the question that is we need to iupac name...