00:01
Out of the multiple questions uploaded by you, i am solving the first two only.
00:07
The first one, for the object which is moving in a circular motion as it starts from rest.
00:36
So initial angular velocity, omega -0, that is 0, and in time is equal to t, final angular velocity, that is omega.
01:01
So first of all, we should find angular acceleration using first equation of motion, omega is equal to omega -not plus alpha -t, means omega -is -able -0 plus alpha -in -2 -t.
01:16
So angular acceleration is omega -by -t.
01:22
So angular displacement will be found using second equation of rotational motion.
01:44
And it will be given by theta is equal to omega -not -t -t plus half alpha t -square.
01:57
Means this theta is equal to 0 for omega -not -tt plus half alpha.
02:02
Alpha we have found to be equal to omega -t by t into t -square, canceling this t.
02:11
Theta is omega -tt by 2...