Question

6. A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts.)

Name: 6. A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts.)
Uploaded: 2020-06-08T17:12:23-08:00
Duration: 1 min 42 s
Channel: Kelly Gottschalk
Description: 6. A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts.)

          6. A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts.)

6. A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts.)

Added by Devin B.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Kelly Gottschalk

06/08/2020

Step 1

The frequency (f) is given as 8 cycles per second. The angular frequency (ω) is related to the frequency by the equation ω = 2πf. Substituting the given frequency, we have ω = 2π(8) = 16π. Show more…

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A point P moving in simple harmonic motion has a frequency of 8 cycles per second. If the amplitude is 50 cm, find an equation that describes the motion of P as a function of time. Assume that the point P is at maximum displacement when t = 0. (6 pts)